1968 United States presidential election in Wyoming

United States presidential election in Wyoming, 1968

← 1964 November 5, 1968 1972 →

Nominee Richard Nixon Hubert Humphrey George Wallace Party Republican Democratic American Independent Home state New York[a] Minnesota Alabama Running mate Spiro Agnew Edmund Muskie Curtis LeMay Electoral vote 3 0 0 Popular vote 70,927 45,173 11,105 Percentage 55.8% 35.5% 8.7%

President before election Lyndon B. Johnson Democratic Elected President Richard Nixon Republican

Elections in Wyoming
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v t e

The 1968 United States presidential election in Wyoming took place on November 5, 1968. All 50 states and the District of Columbia were part of the 1968 United States presidential election. Wyoming voters chose three electors to the Electoral College, who voted for president and vice president.

Wyoming was won by the Republican nominees Richard Nixon of New York and his running mate Spiro Agnew of Maryland. Nixon and Agnew defeated the Democratic nominees, incumbent Vice President Hubert Humphrey of Minnesota and his running mate Edmund Muskie of Maine.

Nixon carried Wyoming with 55.76 percent of the vote to Humphrey's 35.51 percent, a victory margin of 20.25 percent. Also on the ballot was former and future Alabama Governor George Wallace of the American Independent Party. Although Wallace carried five states in the South, he had only modest appeal in Wyoming. His performance was the best by any third-party candidate in Wyoming since Robert La Follette won nearly a third of the vote in 1924, but nonetheless did not equal his vote share in the fellow Western states of Alaska, Idaho and Nevada.

With 55.76% of the popular vote, Wyoming would prove to be Nixon's fifth strongest state in the 1968 election after Nebraska, Idaho, Utah and North Dakota.^[1]

Statewide Results

Results by county

References

Notes

This page was last edited on 16 August 2019, at 13:55