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1960 United States presidential election in Wisconsin

From Wikipedia, the free encyclopedia

1960 United States presidential election in Wisconsin

← 1956 November 8, 1960 1964 →
Nominee Richard Nixon John F. Kennedy
Party Republican Democratic
Home state California Massachusetts
Running mate Henry Cabot Lodge Jr. Lyndon B. Johnson
Electoral vote 12 0
Popular vote 895,175 830,805
Percentage 51.77% 48.05%

President before election

Dwight D. Eisenhower

Elected President

John F. Kennedy

The 1960 United States presidential election in Wisconsin was held on November 8, 1960 as part of the 1960 United States presidential election. State voters chose twelve electors to the Electoral College, who voted for president and vice president.

Republican Party candidate Richard Nixon won Wisconsin with 52% of the popular vote, winning the state's twelve electoral votes.[1] As of the 2016 presidential election, this was the last time a Democrat won the presidency without winning Wisconsin, along with the last time Wisconsin would back the overall losing candidate in a presidential election until 1988.

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  • ✪ Spotlight On 1960 U.S. Presidential Election (1960)
  • ✪ United States presidential election, 1960
  • ✪ The American Presidential Election of 1956
  • ✪ The American Presidential Election of 1964
  • ✪ The American Presidential Election of 1840



1960 United States presidential election in Wisconsin
Party Candidate Votes Percentage Electoral votes
Republican Richard Nixon 895,175 51.77% 12
Democratic John F. Kennedy 830,805 48.05% 0
Socialist Workers Farrell Dobbs 1,792 0.1% 0
Socialist Labor Eric Hass 1,310 0.08% 0
Totals 1,729,082 100.0% 12


  1. ^ David Leip (2012). "1960 Presidential General Election Results - Wisconsin". Dave Leip's Atlas of U. S. Presidential Elections. Retrieved August 19, 2016.

This page was last edited on 23 December 2019, at 22:27
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