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1959 Wimbledon Championships – Girls' singles

From Wikipedia, the free encyclopedia

Girls' singles
1959 Wimbledon Championships
Final
ChampionSouth Africa Joan Cross
Runner-upAustria Doris Schuster
Score6–1, 6–1
Details
Draw12
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1958 · Wimbledon Championships · 1960 →

Joan Cross defeated Doris Schuster in the final, 6–1, 6–1 to win the girls' singles tennis title at the 1959 Wimbledon Championships.[1]

Draw

Key

Draw

First round Quarterfinals Semifinals Final
South Africa Joan Cross 6 6
Republic of Ireland J Atkinson 1 1
South Africa Joan Cross 6 6
Denmark S Westh 6 6 Denmark S Westh 1 0
Switzerland M Berli 2 4 Denmark S Westh 2 6 6
Belgium Micheline Ruquois 6 6 Belgium Micheline Ruquois 6 4 4
Netherlands Marjan Moritz 2 3 South Africa Joan Cross 6 6
Poland E Nowopolska 0 0 Austria Doris Schuster 1 1
Austria Doris Schuster 6 6 Austria Doris Schuster 6 6
India D Appiah 6 7 India D Appiah 4 2
Norway B Sønderaal 2 5 Austria Doris Schuster 7 4 6
United Kingdom Carol Webb 5 6 3
France F Marsot 1 0
United Kingdom Carol Webb 6 6

References

  1. ^ "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.

External links

This page was last edited on 3 December 2022, at 16:42
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