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| Elections in Iowa |
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The 1956 United States presidential election in Iowa took place on November 6, 1956, as part of the 1956 United States presidential election. Iowa voters chose ten[4] representatives, or electors, to the Electoral College, who voted for president and vice president.
Iowa was won by incumbent President Dwight D. Eisenhower (R–Pennsylvania), running with Vice President Richard Nixon, with 59.06% of the popular vote, against Adlai Stevenson (D–Illinois), running with Senator Estes Kefauver, with 40.65% of the popular vote.[5][6]
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Transcription
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Dwight D. Eisenhower (inc.) | 729,187 | 59.06% | |
| Democratic | Adlai Stevenson | 501,858 | 40.65% | |
| A.C.P. of Iowa | T. Coleman Andrews | 3,202 | 0.26% | |
| Write-in | 317 | 0.03% | ||
| Total votes | 1,234,564 | 100% | ||
References
- ^ "United States Presidential election of 1956 - Encyclopædia Britannica". Retrieved July 9, 2017.
- ^ Although he was born in Texas and grew up in Kansas before his military career, at the time of the 1952 election Eisenhower was president of Columbia University and was, officially, a resident of New York. During his first term as president, he moved his private residence to Gettysburg, Pennsylvania, and officially changed his residency to Pennsylvania.
- ^ "The Presidents". David Leip. Retrieved September 27, 2017.
Eisenhower's home state for the 1956 Election was Pennsylvania
- ^ "1956 Election for the Forty-Fourth Term (1961-65)". Retrieved July 9, 2017.
- ^ "1956 Presidential General Election Results - Iowa". Retrieved July 9, 2017.
- ^ "The American Presidency Project - Election of 1956". Retrieved July 9, 2017.
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This page was last edited on 15 August 2019, at 09:00