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1926 Iowa gubernatorial election

From Wikipedia, the free encyclopedia

1926 Iowa gubernatorial election
Flag of Iowa (variant).svg

← 1924 November 2, 1926 1928 →
John Hammill.png
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Nominee John Hammill Alex R. Miller
Party Republican Democratic
Popular vote 377,443 150,415
Percentage 71.51% 28.50%

Governor before election

John Hammill

Elected Governor

John Hammill

The 1926 Iowa gubernatorial election was held on November 2, 1926. Incumbent Republican John Hammill defeated Democratic nominee Alex R. Miller with 71.51% of the vote.

General election


  • John Hammill, Republican
  • Alex R. Miller, Democratic


1926 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican John Hammill (incumbent) 377,443 71.51%
Democratic Alex R. Miller 150,415 28.50%
Majority 227,028
Republican hold Swing


  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved May 20, 2020.
This page was last edited on 29 March 2021, at 23:54
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