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1910 Vermont gubernatorial election

From Wikipedia, the free encyclopedia

1910 Vermont gubernatorial election

← 1908 September 6, 1910 (1910-09-06) 1912 →
John Abner Mead USA politician Governor Vermont-crop.jpg
No image.svg
Nominee John A. Mead Charles D. Watson
Party Republican Democratic
Popular vote 35,263 17,425
Percentage 64.2% 31.7%

Governor before election

George H. Prouty

Elected Governor

John A. Mead

The 1910 Vermont gubernatorial election took place on September 6, 1910. Incumbent Republican George H. Prouty, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate John A. Mead defeated Democratic candidate Charles D. Watson to succeed him.


1910 Vermont gubernatorial election[2]
Party Candidate Votes % ±%
Republican John A. Mead 35,263 64.2
Democratic Charles D. Watson 17,425 31.7
Prohibition Edwin R. Towle 1,044 1.9
Socialist Chester E. Ordway 1,055 1.9
N/A Other 141 0.3
Total votes '54,928' '100'


  1. ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 1 January 2015.
  2. ^ "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Retrieved 1 January 2015.

This page was last edited on 19 March 2021, at 20:55
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