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1896 United States presidential election in Vermont

From Wikipedia, the free encyclopedia

1896 United States presidential election in Vermont

← 1892 November 3, 1896 1900 →
 
William McKinley by Courtney Art Studio, 1896.jpg
WilliamJBryan1902.png
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 4 0
Popular vote 51,127 10,640
Percentage 80.08% 16.66%

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

The 1896 United States presidential election in Vermont took place on November 3, 1896 as part of the 1896 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont overwhelmingly voted for the Republican nominee, former Governor of Ohio William McKinley, over the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan. With 80.08% of the popular vote, Vermont would be McKinley’s strongest victory in terms of percentage in the popular vote as well as the best performance of a Republican in the Green Mountain State to date.[1] McKinley won Vermont by a landslide margin of 63.42%, which is the second-best performance by the Republican Party in any presidential election behind only Barry Goldwater in Mississippi in 1964 – ironically the first election when the Green Mountain State deserted the GOP.

Bryan, running on a platform of free silver, appealed strongly to Western miners and farmers in the 1896 election, but had practically no appeal in the Northeastern state of Vermont. In fact, with only 16.66% of the popular vote Bryan's performance in Vermont was the second weakest of any Democratic presidential candidate to date only after John W. Davis' 15.67% in 1924.

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Transcription

Results

1896 United States presidential election in Vermont[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican William McKinley of Ohio Garret Hobart of New Jersey 51,127 80.08% 4 100.00%
Democratic William Jennings Bryan of Nebraska Arthur Sewall of Maine 10,640 16.66% 0 0.00%
National Democratic John McAuley Palmer of Illinois Simon Bolivar Buckner of Kentucky 1,331 2.08% 0 0.00%
Prohibition Joshua Levering of Maryland Hale Johnson of Illinois 733 1.15% 0 0.00%
N/A Others Others 16 0.03% 0 0.00%
Total 63,847 100.00% 4 100.00%

Results by county

County William McKinley
Republican
William Jennings Bryan
Democratic
Various candidates
Other parties
Margin Total votes cast[3]
# % # % # % # %
Addison 4,314 89.17% 404 8.35% 120 2.48% 3,910 80.82% 4,838
Bennington 3,086 80.39% 656 17.09% 97 2.53% 2,430 63.30% 3,839
Caledonia 3,474 78.65% 729 16.50% 214 4.84% 2,745 62.15% 4,417
Chittenden 4,743 75.26% 1,416 22.47% 143 2.27% 3,327 52.79% 6,302
Essex 873 72.99% 277 23.16% 46 3.85% 596 49.83% 1,196
Franklin 3,444 72.16% 1,150 24.09% 179 3.75% 2,294 48.06% 4,773
Grand Isle 426 69.04% 158 25.61% 33 5.35% 268 43.44% 617
Lamoille 2,061 80.79% 440 17.25% 50 1.96% 1,621 63.54% 2,551
Orange 3,067 80.20% 567 14.83% 190 4.97% 2,500 65.38% 3,824
Orleans 3,412 86.25% 442 11.17% 102 2.58% 2,970 75.08% 3,956
Rutland 6,794 78.00% 1,661 19.07% 255 2.93% 5,133 58.93% 8,710
Washington 4,476 73.10% 1,396 22.80% 251 4.10% 3,080 50.30% 6,123
Windham 4,829 84.14% 670 11.67% 240 4.18% 4,159 72.47% 5,739
Windsor 6,128 88.02% 674 9.68% 160 2.30% 5,454 78.34% 6,962
Totals 51,127 80.08% 10,640 16.66% 2,080 3.26% 40,487 63.41% 63,847

References

  1. ^ "1896 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ "1896 Presidential General Election Results - Vermont". U.S. Election Atlas. Retrieved 23 December 2013.
  3. ^ Robinson, Edgar Eugene; The Presidential Vote 1896-1932, pp. 352-354 ISBN 9780804716963


This page was last edited on 18 March 2020, at 16:06
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