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1888 United States presidential election in New Jersey

From Wikipedia, the free encyclopedia

1888 United States presidential election in New Jersey

← 1884 November 6, 1888 1892 →
 
StephenGroverCleveland.png
Pach Brothers - Benjamin Harrison.jpg
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Allen G. Thurman Levi P. Morton
Electoral vote 9 0
Popular vote 151,508 144,360
Percentage 49.87% 47.52%

President before election

Grover Cleveland
Democratic

Elected President

Benjamin Harrison
Republican

The 1888 United States presidential election in New Jersey took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

New Jersey voted for the Democratic nominee, incumbent President Grover Cleveland, over the Republican nominee, Benjamin Harrison. Cleveland won his birth state by a very narrow margin of 2.35%.

The Republican nominee would not win the White House without New Jersey again until 2000, when Al Gore won New Jersey by a landslide in fact, but lost the election.

Results

1888 United States presidential election in New Jersey[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Grover Cleveland of New York Allen Granberry Thurman of Ohio 151,508 49.87% 9 100.00%
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 144,360 47.52% 0 0.00%
Prohibition Clinton Bowen Fisk of New Jersey John Anderson Brooks of Missouri 7,933 2.61% 0 0.00%
Total 303,801 100.00% 9 100.00%

References

  1. ^ "1888 Presidential General Election Results - New Jersey". U.S. Election Atlas. Retrieved 23 December 2013.


This page was last edited on 23 December 2019, at 21:25
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