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1888 United States presidential election in Arkansas

From Wikipedia, the free encyclopedia

1888 United States presidential election in Arkansas

← 1884 November 6, 1888 1892 →
Pach Brothers - Benjamin Harrison.jpg
Nominee Grover Cleveland Benjamin Harrison Alson Streeter
Party Democratic Republican Labor
Home state New York Indiana Illinois
Running mate Allen G. Thurman Levi P. Morton Charles E. Cunningham
Electoral vote 7 0 0
Popular vote 86,062 59,752 10,630
Percentage 54.80% 38.04% 6.77%

Arkansas Presidential Election Results 1888.svg
County Results

President before election

Grover Cleveland

Elected President

Benjamin Harrison

The 1888 United States presidential election in Arkansas took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Arkansas voted for the Democratic nominee, incumbent President Grover Cleveland, over the Republican nominee, Benjamin Harrison. Cleveland won the state by a margin of 16.76%.


1888 United States presidential election in Arkansas[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Grover Cleveland of New York Allen Granberry Thurman of Ohio 86,062 54.80% 7 100.00%
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 59,752 38.04% 0 0.00%
Labor Alson Streeter of Illinois Charles E. Cunningham of Arkansas 10,630 6.77% 0 0.00%
Prohibition Clinton Fisk of New Jersey John A. Brooks of Missouri 614 0.39% 0 0.00%
Total 157,058 100.00% 7 100.00%

See also



  1. ^ "1888 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved 25 November 2020.

This page was last edited on 26 February 2021, at 11:52
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