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1885 Wimbledon Championships – Women's singles

From Wikipedia, the free encyclopedia

Women's singles
1885 Wimbledon Championships  
Final
ChampionUnited Kingdom Maud Watson
Runner-upUnited Kingdom Blanche Bingley
Score6–1, 7–5
Details
Draw10
Seeds
Events
Singles men women
Doubles men women
← 1884 · Wimbledon Championships · 1886 →

Maud Watson defeated Blanche Bingley 6–1, 7–5 to win the ladies' singles tennis title at the 1885 Wimbledon Championships.[1][2]

Draw

Key

Draw

First round Quarterfinals Semifinals Final
United Kingdom Blanche Bingley 6 6
United Kingdom LM Nash 2 2 United Kingdom Blanche Bingley
United Kingdom Mrs Dransfield w/o
United Kingdom Blanche Bingley 6 6
United Kingdom Jane Meikle 6 4 6 United Kingdom Edith Gurney 1 2
United Kingdom Lilian Watson 3 6 4 United Kingdom Jane Meikle 5 4
United Kingdom Edith Gurney 7 6
United Kingdom Blanche Bingley 1 5
United Kingdom Maud Watson 6 7
United Kingdom EF Hudson 6 6
United Kingdom Constance Bryan 3 0
United Kingdom EF Hudson 0 1
United Kingdom Maud Watson 6 6
United Kingdom May Langrishe 0 2
United Kingdom Maud Watson 6 6

References

  1. ^ 100 Years of Wimbledon by Lance Tingay, Guinness Superlatives Ltd. 1977
  2. ^ Barrett, John (2014). Wimbledon: The Official History (4th ed.). Vision Sports Publishing. ISBN 9-781909-534230.

External links

This page was last edited on 2 August 2023, at 13:15
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