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1876 United States presidential election in New Jersey

From Wikipedia, the free encyclopedia

1876 United States presidential election in New Jersey

← 1872 November 7, 1876 1880 →
 
SamuelJonesTilden.png
RutherfordBHayes.png
Nominee Samuel J. Tilden Rutherford B. Hayes
Party Democratic Republican
Home state New York Ohio
Running mate Thomas A. Hendricks William A. Wheeler
Electoral vote 9 0
Popular vote 115,962 103,517
Percentage 52.66% 47.01%

President before election

Ulysses S. Grant
Republican

Elected President

Rutherford B. Hayes
Republican

The 1876 United States presidential election in New Jersey took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose 9 representatives, or electors to the Electoral College, who voted for president and vice president.

New Jersey voted for the Democratic nominee, Samuel J. Tilden, over the Republican nominee, Rutherford B. Hayes. Tilden won the state by a narrow margin of 5.65%.

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  • ✪ The American Presidential Election of 1916
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Transcription

Results

1876 United States presidential election in New Jersey[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Samuel J. Tilden of New York Thomas A. Hendricks of Indiana 115,962 52.66% 9 100.00%
Republican Rutherford B. Hayes of Ohio William A. Wheeler of New York 103,517 47.01% 0 0.00%
Greenback Peter Cooper of New York Samuel Fenton Cary of Ohio 714 0.32% 0 0.00%
Total 220,193 100.00% 9 100.00%

References

  1. ^ "1876 Presidential General Election Results - New Jersey".


This page was last edited on 2 February 2020, at 18:54
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