1876 United States presidential election in Nebraska

1876 United States presidential election in Nebraska

← 1872 November 7, 1876 1880 →

Nominee Rutherford B. Hayes Samuel J. Tilden Party Republican Democratic Home state Ohio New York Running mate William A. Wheeler Thomas A. Hendricks Electoral vote 3 0 Popular vote 31,915 17,413 Percentage 64.70% 35.30%

County Results Hayes   40-50%   50-60%   60-70%   70-80%   80-90%   90-100% Tilden   40-50%   50-60%   60-70%   70-80%

President before election Ulysses S. Grant Republican Elected President Rutherford B. Hayes Republican

Elections in Nebraska
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The 1876 United States presidential election in Nebraska took place on November 7, 1876 as part of the 1876 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Nebraska voted for the Republican nominee, Ohio Governor Rutherford B. Hayes, over the Democratic nominee, New York Governor Samuel J. Tilden by a margin of 29.4%.

With 64.70% of the popular vote, Nebraska would be Hayes' second strongest victory in terms of percentage in the popular vote after Vermont.^[1]

Results

See also

• United States presidential elections in Nebraska

References

This page was last edited on 3 September 2023, at 14:49