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1872 United States presidential election in New Jersey

From Wikipedia, the free encyclopedia

1872 United States presidential election in New Jersey

← 1868 November 5, 1872 1876 →
 
UlyssesGrant.jpg
Horace Greeley restored (cropped).jpg
Nominee Ulysses S. Grant Horace Greeley
Party Republican Liberal Republican
Home state Ohio New York
Running mate Henry Wilson Benjamin G. Brown
Electoral vote 9 0
Popular vote 91,656 76,456
Percentage 54.52% 45.48%

President before election

Ulysses S. Grant
Republican

Elected President

Ulysses S. Grant
Republican

The 1872 United States presidential election in New Jersey took place on November 5, 1872. All contemporary 37 states were part of the 1872 United States presidential election. The state voters chose nine electors to the Electoral College, which selected the president and vice president.

New Jersey was won by the Republican nominees, incumbent President Ulysses S. Grant of Illinois and his running mate Senator Henry Wilson of Massachusetts. Grant and Wilson defeated the Liberal Republican and Democratic nominees, former Congressman Horace Greeley of New York and his running mate former Senator and Governor Benjamin Gratz Brown of Missouri by a margin of 9.04%.

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Transcription

Results

1872 United States presidential election in New Jersey[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Ulysses S. Grant of Illinois Henry Wilson of Massachusetts 91,656 54.52% 9 100.00%
Liberal Republican Horace Greeley of New York Benjamin Gratz Brown of Missouri 76,456 45.48% 0 0.00%
Total 168,112 100.00% 9 100.00%

References

  1. ^ "1872 Presidential General Election Results - New Jersey".


This page was last edited on 3 September 2019, at 18:35
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