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1868 United States presidential election in Oregon

From Wikipedia, the free encyclopedia

1868 United States presidential election in Oregon

← 1864 November 3, 1868 1872 →
 
Horatio Seymour - Brady-Handysmall.jpg
Ulysses S Grant by Brady c1870-restored (cropped).jpg
Nominee Horatio Seymour Ulysses S. Grant
Party Democratic Republican
Home state New York Illinois
Running mate Francis Preston Blair, Jr. Schuyler Colfax
Electoral vote 3 0
Popular vote 11,125 10,961
Percentage 50.37% 49.63%

Oregon Presidential Election Results 1868.svg
County Results

President before election

Andrew Johnson
Democratic

Elected President

Ulysses S. Grant
Republican

The 1868 United States presidential election in Oregon took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Oregon voted for the Democratic nominee, Horatio Seymour over the Republican nominee, Ulysses S. Grant. Seymour won the state by a narrow margin of 0.74%.

As a result of his win, Seymour became the first Democratic presidential candidate to ever win Oregon. Another Democrat would not win Oregon again on a presidential level until Woodrow Wilson won the state in 1912.

Results

1868 United States presidential election in Oregon[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Horatio Seymour of New York Francis Preston Blair, Jr. of Missouri 11,125 50.37% 3 100.00%
Republican Ulysses S. Grant of Illinois Schuyler Colfax of Indiana 10,961 49.63% 0 0.00%
Total 22,086 100.00% 3 100.00%


References

  1. ^ "1868 Presidential General Election Results - Oregon".


This page was last edited on 13 April 2021, at 21:10
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