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1868 United States presidential election in Missouri

From Wikipedia, the free encyclopedia

United States presidential election in Missouri, 1868
← 1864 November 3, 1868 1872 →
Ulysses S Grant by Brady c1870-restored (cropped).jpg
Horatio Seymour - Brady-Handysmall.jpg
Nominee Ulysses S. Grant Horatio Seymour
Party Republican Democratic
Home state Ohio New York
Running mate Schuyler Colfax Francis Preston Blair Jr.
Electoral vote 11 0
Popular vote 86,860 65,628
Percentage 56.96% 43.04%

Missouri Presidential Election Results 1868.svg
County Results

President before election

Andrew Johnson

Elected President

Ulysses S. Grant

The 1868 United States presidential election in Missouri took place on November 3, 1868, as part of the 1868 United States presidential election. Missouri voters chose eleven representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Missouri was won by Ulysses S. Grant, formerly the 6th Commanding General of the United States Army (R-Ohio), running with Speaker of the House Schuyler Colfax, with 56.96% of the popular vote, against the 18th governor of New York, Horatio Seymour (DNew York), running with former Senator Francis Preston Blair, Jr., with 43.04% of the vote.[1]

Grant's victory in Missouri made him the first Republican presidential candidate to win the state, although President Abraham Lincoln had won the state on the National Union ticket in 1864. Grant would also be the only Republican to carry the state until Theodore Roosevelt won it in 1904.


United States presidential election in Missouri, 1868[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Ulysses S. Grant of Ohio Schuyler Colfax of Indiana 86,860 56.96% 11 100.00%
Democratic Horatio Seymour of New York Francis Preston Blair, Jr. of Missouri 65,628 43.04% 0 0.00%
Total 152,488 100.00% 11 100.00%


  1. ^ a b c "1868 Presidential Election Results Missouri".

This page was last edited on 13 April 2021, at 21:19
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