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1860 United States presidential election in South Carolina

From Wikipedia, the free encyclopedia

1860 United States presidential election in South Carolina

← 1856 November 6, 1860 1868 →
 
John C Breckinridge-04775-restored.jpg
Nominee John C. Breckinridge
Party Southern Democratic
Home state Kentucky
Running mate Joseph Lane
Electoral vote 8

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in South Carolina took place on November 6, 1860, as part of the 1860 United States presidential election. The state legislature chose 8 representatives, or electors to the Electoral College, who voted for president and vice president. By 1860 only one state, South Carolina, used this procedure in a presidential election. This would be, as of 2020, the final time a state exercised its option to restrict its presidential franchise to state legislators.

South Carolina cast 8 electoral votes for the Southern Democratic candidate John C. Breckinridge. These electors were chosen by the South Carolina General Assembly, the state legislature, rather than by popular vote.[1] However, Republican Party candidate Abraham Lincoln would win the election nationally and would cause a major upset in the Southern States. South Carolina would be the first state to secede from the Union, on December 20, 1860, and would join the newly formed Confederate States of America in the February of the following year. South Carolina would not vote in another presidential election until 1868.

Results

1860 United States presidential election in South Carolina[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Southern Democratic John Cabell Breckinridge of Kentucky Joseph Lane of Oregon 8 100.00%

References

  1. ^ a b "1860 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 23 December 2013.


This page was last edited on 17 March 2021, at 05:33
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