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1860 United States presidential election in Arkansas

From Wikipedia, the free encyclopedia

1860 United States presidential election in Arkansas

← 1856 November 6, 1860 1868 →
 
John C Breckinridge-04775-restored.jpg
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Nominee John C. Breckinridge John Bell Stephen A. Douglas
Party Southern Democratic Constitutional Union Democratic
Home state Kentucky Tennessee Illinois
Running mate Joseph Lane Edward Everett Herschel V. Johnson
Electoral vote 4 0 0
Popular vote 28,732 20,063 5,357
Percentage 53.06% 30.89% 9.89%

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in Arkansas took place on November 6, 1860, as part of the 1860 United States presidential election. Arkansas voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.

Arkansas was won by the 14th Vice President of the United States John C. Breckinridge (SDKentucky), running with Senator Joseph Lane, with 53.06% of the popular vote, against Senator John Bell (CUTennessee), running with the Governor of Massachusetts Edward Everett, with 37.05% of the popular vote and the 15th Senator Stephen A. Douglas (DVermont), running with 41st Governor of Georgia Herschel Johnson, with 9.89% of the popular vote.

Republican Party candidate Abraham Lincoln was not on the ballot in the state.

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Transcription

Results

1860 United States presidential election in Arkansas[1]
Party Candidate Votes %
Southern Democratic John C. Breckinridge 28,732 53.06%
Constitutional Union John Bell 20,063 37.05%
Democratic Stephen A. Douglas 5,357 9.89%
Total votes 54,152 100%

References

  1. ^ "1860 Presidential Election Results Arkansas".
This page was last edited on 25 September 2019, at 19:35
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