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Municipal results Buckingham: 50–60% 60–70% 70–80% Seymour: 50–60% 60–70% 70–80% Tie | |||||||||||||||||
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| Elections in Connecticut |
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The 1860 Connecticut gubernatorial election was held on April 2, 1860.[1][2] Incumbent governor and Republican nominee William Alfred Buckingham defeated former governor and Democratic nominee Thomas H. Seymour with 50.30% of the vote.
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Transcription
General election
Candidates
Major party candidates
- William Alfred Buckingham, Republican
- Thomas H. Seymour, Democratic
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | William Alfred Buckingham (incumbent) | 44,458 | 50.30% | ||
| Democratic | Thomas H. Seymour | 43,920 | 49.70% | ||
| Majority | 538 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References
- ^ "Republican State Ticket". Litchfield enquirer. Litchfield, Conn. March 29, 1860. p. 2. Retrieved May 3, 2022.
- ^ "The Campaign in Connecticut". The New York herald. New York, N.Y. April 2, 1860. p. 1. Retrieved May 3, 2022.
- ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. p. 25. ISBN 9780786414390.
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This page was last edited on 4 April 2024, at 01:00