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1856 United States presidential election in Texas

From Wikipedia, the free encyclopedia

1856 United States presidential election in Texas

← 1852 November 4, 1856 1860 →
Hon. James Buchanan - NARA - 528318-crop.jpg
Millard Fillmore by Brady Studio 1855-65-crop.jpg
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew J. Donelson
Electoral vote 4 0
Popular vote 31,169 15,639
Percentage 66.59% 33.41%

President before election

Franklin Pierce

Elected President

James Buchanan

The 1856 United States presidential election in Texas was held in November 4, 1856 as part of the 1856 United States presidential election. State voters chose four electors to represent the state in the Electoral College, which chose the president and vice president.

Texas voted for the Democratic nominee James Buchanan, who received 67% of the vote. Texas was Buchanan's second strongest state.

Republican Party nominee John C. Frémont was not on the ballot.

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  • ✪ The American Presidential Election of 1904
  • ✪ The American Presidential Election of 1864
  • ✪ The American Presidential Election of 1844
  • ✪ The American Presidential Election of 2000
  • ✪ The American Presidential Election of 1868



1856 United States presidential election in Texas[1]
Party Candidate Votes Percentage Electoral votes
Democratic James Buchanan 31,169 66.589% 4
American Millard Fillmore 15,639 33.411% 0
Total 46,808 100.0% 4


  1. ^ "David Leip's Atlas of U.S. Presidential Elections".

This page was last edited on 26 September 2019, at 22:05
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