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1856 United States presidential election in Louisiana

From Wikipedia, the free encyclopedia

United States presidential election in Louisiana, 1856

← 1852 November 4, 1856 1860 →
Hon. James Buchanan - NARA - 528318-crop.jpg
Millard Fillmore by Brady Studio 1855-65-crop.jpg
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew Jackson Donelson
Electoral vote 6 0
Popular vote 22,164 20,709
Percentage 51.70% 48.30%

President before election

Franklin Pierce

Elected President

James Buchanan

The 1852 United States presidential election in Louisiana took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

Louisiana voted for the Democratic candidate, James Buchanan, over American Party candidate Millard Fillmore. Buchanan won Louisiana by a narrow margin of 3.40%.

Republican Party candidate John C. Frémont was not on the ballot in the state.

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United States presidential election in Louisiana, 1856[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 22,164 51.70% 6 100.00%
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 20,709 48.30% 0 0.00%
Total 42,873 100.00% 6 100.00%


  1. ^ "1856 Presidential General Election Results - Mississippi". U.S. Election Atlas. Retrieved 2 December 2017.
  2. ^ "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.

This page was last edited on 23 December 2019, at 21:15
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