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1856 United States presidential election in Indiana

From Wikipedia, the free encyclopedia

1856 United States presidential election in Indiana

← 1852 November 4, 1856 1860 →
James Buchanan, U.S. Secretary of State.jpg
John Charles Fremont crop.jpg
Millard Fillmore by Brady Studio 1855-65-crop.jpg
Nominee James Buchanan John C. Frémont Millard Fillmore
Party Democratic Republican Know Nothing
Home state Pennsylvania California New York
Running mate John C. Breckinridge William L. Dayton Andrew Jackson Donelson
Electoral vote 13 0 0
Popular vote 118,670 94,375 22,386
Percentage 50.41% 40.09% 9.51%

President before election

Franklin Pierce

Elected President

James Buchanan

The 1856 United States presidential election in Indiana took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose thirteen representatives, or electors to the Electoral College, who voted for president and vice president.

Indiana voted for the Democratic candidate, James Buchanan, over Republican candidate John C. Frémont and American Party candidate Millard Fillmore. Buchanan won Indiana by a margin of 10.32%.

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1856 United States presidential election in Indiana[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 118,670 50.41% 13 100.00%
Republican John C. Frémont of California William L. Dayton of New Jersey 94,375 40.09% 0 0.00%
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 22,386 9.51% 0 0.00%
Total 235,431 100.00% 13 100.00%


  1. ^ "1856 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 3 December 2017.
  2. ^ "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 3 December 2017.

This page was last edited on 1 January 2021, at 13:13
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