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1844 United States presidential election in Pennsylvania

From Wikipedia, the free encyclopedia

1844 United States presidential election in Pennsylvania

← 1840 November 1 – December 4, 1844 1848 →
 
JamesKnoxPolk.jpg
Clay portrait.jpg
Nominee James K. Polk Henry Clay
Party Democratic Whig
Home state Tennessee Kentucky
Running mate George M. Dallas Theodore Frelinghuysen
Electoral vote 26 0
Popular vote 167,447 161,125
Percentage 50.50% 48.59%

President before election

John Tyler
Independent

Elected President

James K. Polk
Democratic

The 1844 United States presidential election in Pennsylvania took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Democratic candidate, James K. Polk, over the Whig candidate, Henry Clay. Polk won Pennsylvania by a margin of 1.91%.

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Transcription

Results

United States presidential election in Pennsylvania, 1844[1]
Party Candidate Votes Percentage Electoral votes
Democratic James K. Polk 167,447 50.50% 26
Whig Henry Clay 161,125 48.59% 0
Liberty James G. Birney 3,000 0.90% 0
Totals 331,572 100.0% 26

References

  1. ^ "1844 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 4 August 2012.


This page was last edited on 16 May 2019, at 19:45
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