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1844 United States presidential election in Pennsylvania

From Wikipedia, the free encyclopedia

1844 United States presidential election in Pennsylvania

← 1840 November 1 – December 4, 1844 1848 →
Clay portrait.jpg
Nominee James K. Polk Henry Clay
Party Democratic Whig
Home state Tennessee Kentucky
Running mate George M. Dallas Theodore Frelinghuysen
Electoral vote 26 0
Popular vote 167,447 161,125
Percentage 50.50% 48.59%

President before election

John Tyler

Elected President

James K. Polk

The 1844 United States presidential election in Pennsylvania took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Democratic candidate, James K. Polk, over the Whig candidate, Henry Clay. Polk won Pennsylvania by a margin of 1.91%.

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  • ✪ The American Presidential Election of 1844
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  • ✪ American History - Part 067 - Polk Elected President - Texas sneaks in
  • ✪ How New Jersey has voted in Every Presidential Election



1844 United States presidential election in Pennsylvania[1]
Party Candidate Votes Percentage Electoral votes
Democratic James K. Polk 167,447 50.50% 26
Whig Henry Clay 161,125 48.59% 0
Liberty James G. Birney 3,000 0.90% 0
Totals 331,572 100.0% 26


  1. ^ "1844 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 4 August 2012.

This page was last edited on 10 September 2019, at 15:15
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