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1840 United States presidential election in Tennessee

From Wikipedia, the free encyclopedia

United States presidential election in Tennessee, 1840

← 1836 October 30 - December 2, 1840 1844 →
 
Harrison crop.jpg
Van Buren.jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 15 0
Popular vote 60,194 47,951
Percentage 55.66% 44.34%

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

The 1840 United States presidential election in Tennessee took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose fifteen representatives, or electors to the Electoral College, who voted for President and Vice President.

Tennessee voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Tennessee by a margin of 11.32%.

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  • ✪ The American Presidential Election of 1864
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Transcription

Results

United States presidential election in Tennessee, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 60,194 55.66% 15 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 47,951 44.34% 0 0.00%
Total 108,145 100.00% 15 100.00%

References

  1. ^ "1840 Presidential General Election Results - Tennessee". U.S. Election Atlas. Retrieved 23 December 2013.


This page was last edited on 26 June 2019, at 21:25
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