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1836 United States presidential election in Massachusetts

From Wikipedia, the free encyclopedia

1836 United States presidential election in Massachusetts

← 1832 November 3 – December 7, 1836 1840 →
Turnout43.4%[1] Increase 4.0 pp
Black Dan crop.jpg
Van Buren.jpg
Nominee Daniel Webster Martin Van Buren
Party Whig Democratic
Home state Massachusetts New York
Running mate Francis Granger Richard Johnson
Electoral vote 14 0
Popular vote 41,201 33,486
Percentage 55.13% 44.81%

The 1836 United States presidential election in Massachusetts took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose fourteen representatives, or electors to the Electoral College, who voted for President and Vice President.

Massachusetts voted for Whig candidate and state native Daniel Webster over the Democratic candidate, Martin Van Buren. Webster won Massachusetts by a margin of 10.32%.

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  • ✪ The American Presidential Election of 1860
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1836 United States presidential election in Massachusetts[2]
Party Candidate Votes Percentage Electoral votes
Whig Daniel Webster 41,201 55.13% 14
Democratic Martin Van Buren 33,486 44.81% 0
N/A Other 45 0.06% 0
Totals 74,732 100.0% 14


  1. ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. ^ "1836 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 4 August 2012.
This page was last edited on 23 December 2019, at 21:10
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