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1800 United States presidential election in Pennsylvania

From Wikipedia, the free encyclopedia

1800 United States presidential election in Pennsylvania

← 1796 1800 1804 →
 
Thomas Jefferson by Rembrandt Peale, 1800.jpg
John Adams crop.jpg
Nominee Thomas Jefferson John Adams
Party Democratic-Republican Federalist
Home state Virginia Massachusetts
Electoral vote 8 7
Percentage 64.52% 35.48%

 
Vanderlyn Burr.jpg
CharlesCPinckney crop.jpg
Nominee Aaron Burr Charles Cotesworth Pinckney
Party Democratic-Republican Federalist
Home state New York South Carolina
Electoral vote 8 7
Percentage

President before election

John Adams
Federalist

Elected President

Thomas Jefferson
Democratic-Republican

The 1800 United States presidential election in Pennsylvania took place as part of the 1800 United States presidential election. The Pennsylvania General Assembly, consisting of the State Senate and State House chose 15 representatives, or electors to the Electoral College,[1] who voted for President and Vice President. The 1800 election marks the only time in Pennsylvania history that presidential electors were chosen by the State Legislature.[2]

Pennsylvania elected eight electors supportive the Democratic-Republican candidate, Thomas Jefferson and seven electors supportive of the Federalist candidate, John Adams.

Results

United States presidential election in Pennsylvania, 1800[2]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican Thomas Jefferson 60 64.52% 8
Federalist John Adams 33 35.48% 7
N/A Not voting 7 - -
N/A Not sworn in 2 - -
Totals 93 100.0% 15

Note: These are the vote totals for each candidate for the entire State Assembly, including the State Senate and the State House.

References

  1. ^ "1800 ELECTION FOR THE FOURTH TERM, 1801-1805". National Archives. Retrieved 4 August 2012.
  2. ^ a b "Pennsylvania Presidential Election Returns 1800" (PDF). Wilkes University. Retrieved 4 August 2012.


This page was last edited on 15 May 2019, at 21:10
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