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1792 United States presidential election in Pennsylvania

From Wikipedia, the free encyclopedia

1792 United States presidential election in Pennsylvania

← 1789 1792 1796 →
 
Gilbert Stuart Williamstown Portrait of George Washington.jpg
Official Presidential portrait of John Adams (by John Trumbull, circa 1792).jpg
George Clinton by Ezra Ames (full portrait).jpg
Nominee George Washington John Adams George Clinton
Party Nonpartisan Federalist Democratic-Republican
Home state Virginia Massachusetts New York
Electoral vote 15 14 1
Popular vote 4,576
Percentage 100%

The 1792 United States presidential election in Pennsylvania took place as part of the 1792 United States presidential election. Pennsylvania voters chose 15 members of the Electoral College,[1] each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

Pennsylvania unanimously voted for nonpartisan candidate and incumbent President George Washington. The total statewide popular vote comprised 3,479 for Federalist electors and 1,097 for Anti-Federalist electors, all of whom were supportive of Washington and all but one of whom supported John Adams, the incumbent Vice President; one elector voted for George Clinton.[2]

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Transcription

Results

1792 United States presidential election in Pennsylvania[2]
Party Candidate Votes Percentage Electoral votes
Nonpartisan George Washington 4,576 100% 15
Totals 4,576 100.0% 15

References

  1. ^ "1792 ELECTION FOR THE SECOND TERM, 1793-1797". National Archives. Retrieved 4 August 2012.
  2. ^ a b "PA US President". Our Campaigns. Retrieved 4 August 2012.


This page was last edited on 2 February 2020, at 20:50
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