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Benton Township, Elkhart County, Indiana

From Wikipedia, the free encyclopedia

Benton Township
Location of Benton Township in Elkhart County
Location of Benton Township in Elkhart County
Coordinates: 41°28′55″N 85°42′27″W / 41.48194°N 85.70750°W / 41.48194; -85.70750
CountryUnited States
StateIndiana
CountyElkhart
Government
 • TypeIndiana township
Area
 • Total35.9 sq mi (93 km2)
 • Land35.84 sq mi (92.8 km2)
 • Water0.06 sq mi (0.2 km2)
Elevation853 ft (260 m)
Population
 (2020)
 • Total3,200
 • Density89/sq mi (34/km2)
FIPS code18-04798[2]
GNIS feature ID453105

Benton Township is one of sixteen townships in Elkhart County, Indiana. As of the 2020 census, its population was 3,200, up from 2,963 at the previous census.[3]

According to the 2020 "ACS 5-Year Estimates Data Profiles", 70.1% of the township's population spoke only English, while 23.7 spoke an "other [than Spanish] Indo-European language"[4] (basically Pennsylvania German/German).

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Transcription

Geography

According to the 2010 census, the township has a total area of 35.9 square miles (93 km2), of which 35.84 square miles (92.8 km2) (or 99.83%) is land and 0.06 square miles (0.16 km2) (or 0.17%) is water.[3]

Cities and towns

Unincorporated towns

Adjacent townships

Major highways

Cemeteries

The township contains two cemeteries: Brown and Hire.

Demographics

Historical population
CensusPop.Note
20102,963
20203,2008.0%
U.S. Censuses: 2010,[3]
and 2020[4]

References

  • "Benton Township, Elkhart County, Indiana". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved September 24, 2009.
  • United States Census Bureau cartographic boundary files

External links


This page was last edited on 22 July 2023, at 17:38
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