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2013 Porsche Tennis Grand Prix – Doubles

From Wikipedia, the free encyclopedia

Iveta Benešová and Barbora Záhlavová-Strýcová were the defending champions, but Benešová decided not to participate.
Záhlavová-Strýcová played alongside Julia Görges, but they lost in the first round to Liezel Huber and Janette Husárová.
Mona Barthel and Sabine Lisicki won the title, defeating Bethanie Mattek-Sands and Sania Mirza in the final, 6–4, 7–5.

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Transcription

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
Alt United States J Craybas
United States M Moulton-Levy
1 1
WC Germany M Barthel
Germany S Lisicki
6 6 WC Germany M Barthel
Germany S Lisicki
6 2 [10]
Germany K Barrois
Kazakhstan Y Shvedova
3 65 WC Serbia J Janković
Croatia M Lučić-Baroni
1 6 [4]
WC Serbia J Janković
Croatia M Lučić-Baroni
6 77 WC Germany M Barthel
Germany S Lisicki
6 6
4 United States R Kops-Jones
United States A Spears
6 6 Croatia D Jurak
Hungary K Marosi
3 4
Zimbabwe C Black
Australia A Rodionova
1 0 4 United States R Kops-Jones
United States A Spears
6 4 [9]
Croatia D Jurak
Hungary K Marosi
6 77 Croatia D Jurak
Hungary K Marosi
3 6 [11]
Russia A Pavlyuchenkova
Czech Republic L Šafářová
4 64 WC Germany M Barthel
Germany S Lisicki
6 7
Germany A-L Grönefeld
Czech Republic K Peschke
6 6 United States B Mattek-Sands
India S Mirza
4 5
New Zealand M Erakovic
China S Peng
2 3 Germany A-L Grönefeld
Czech Republic K Peschke
68 2
WC Germany A Kerber
Germany A Petkovic
6 77 WC Germany A Kerber
Germany A Petkovic
710 6
3 Russia E Makarova
Russia E Vesnina
1 62 WC Germany A Kerber
Germany A Petkovic
4 5
Germany J Görges
Czech Republic B Záhlavová-Strýcová
4 6 [6] United States B Mattek-Sands
India S Mirza
6 7
United States L Huber
Slovakia J Husárová
6 4 [10] United States L Huber
Slovakia J Husárová
5 4
United States B Mattek-Sands
India S Mirza
77 7 United States B Mattek-Sands
India S Mirza
7 6
2 Russia N Petrova
Slovenia K Srebotnik
63 5

References

This page was last edited on 27 February 2022, at 22:39
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