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1958 Wimbledon Championships – Girls' singles

From Wikipedia, the free encyclopedia

Girls' singles
1958 Wimbledon Championships
Final
ChampionUnited States Sally Moore
Runner-upSoviet Union Anna Dmitrieva
Score6–2, 6–4
Details
Draw13
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1957 · Wimbledon Championships · 1959 →

Sally Moore defeated Anna Dmitrieva in the final, 6–2, 6–4 to win the girls' singles tennis title at the 1958 Wimbledon Championships.[1]

Draw

Key

Draw

First round Quarterfinals Semifinals Final
United States Sally Moore 6 6
Sweden A Johansson 6 6 Sweden A Johansson 0 2
Socialist Federal Republic of Yugoslavia M Djukić 4 3 United States Sally Moore 6 7
Denmark Pia Balling 4 10 6 Denmark Pia Balling 0 5
France Solange Galtier 6 8 0 Denmark Pia Balling 6 6
Switzerland H Reimann 3 2 Austria Edda Herdy 2 0
Austria Edda Herdy 6 6 United States Sally Moore 6 6
Netherlands H Ruinen 6 4 Soviet Union Anna Dmitrieva 2 4
Soviet Union Anna Dmitrieva 8 6 Soviet Union Anna Dmitrieva 6 6
Republic of Ireland Eleanor O'Neill 6 1 6 Republic of Ireland Eleanor O'Neill 2 4
West Germany Marilen Knobling 4 6 2 Soviet Union Anna Dmitrieva 4 8 6
United Kingdom Jenny Trewby 6 6 2
Norway Liv Christiansen 1 1
United Kingdom Jenny Trewby 6 6

References

  1. ^ "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.

External links

This page was last edited on 6 January 2023, at 02:18
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